University:
California State University, Northridge
Course:
COMP 110 | Introduction to Algorithms and Programming and Lab
Academic year:

2023
Views:

203

Pages:

2
Author:

S Kim

Solve Quadratic Equations The two roots of a quadratic equation ax + bx + c = 0 can be obtained using the following formula: 2 𝑥= -b±√b2-4ac 2a B2 – 4ac is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots. If it is zero, the equation has one root. If it is negative, the equation has no real roots. Write a program that prompts the user to enter values for a, b, and c and display the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is zero, display one root. Otherwise, display “The equation has two imaginary roots, followed by the imaginary roots”. Note that you can use pow(x, 0.5) to compute. Here are some sample runs: STAGE 2 | Testing 1. Compile the program and fix syntax errors 2. Execute the program and check for run-time and logical errors with following samples: 3. Copy and paste a sample run in a document called “Lab4_output”” Enter a, b, c: 1.0 3 1 The equation has two roots -0.38 and -2.62 Enter a, b, c: 1.0 2 1.0 The equation has one root -1.00 Enter a, b, c: 1 -4 8 The equation has two imaginary roots (2.00 + 2.00i) and (2.00 - 2.00i) Submission (CANVAS) Upload your “*.java” program and “Lab4_output”” to canvas import java.util.Scanner; public class QuadraticEquationSolver { public static void main(String[] args) { // Create a Scanner object to get user input Scanner scanner = new Scanner(System.in); // Get input from the user System.out.print("Enter a, b, c: "); double a = scanner.nextDouble(); double b = scanner.nextDouble(); double c = scanner.nextDouble(); // Calculate and display the roots String result = calculateRoots(a, b, c); System.out.println(result); // Close the Scanner scanner.close(); } // Function to calculate roots based on the discriminant private static String calculateRoots(double a, double b, double c) { // Calculate the discriminant double discriminant = b * b - 4 * a * c; // Check the discriminant if (discriminant > 0) { // Two real roots double root1 = (-b + Math.sqrt(discriminant)) / (2 * a); double root2 = (-b - Math.sqrt(discriminant)) / (2 * a); return String.format("The equation has two roots %.2f and %.2f", root1, root2); } else if (discriminant == 0) { // One real root double root = -b / (2 * a); return String.format("The equation has one root %.2f", root); } else { // Two imaginary roots double realPart = -b / (2 * a); double imaginaryPart = Math.sqrt(Math.abs(discriminant)) / (2 * a); return String.format("The equation has two imaginary roots %.2f + %.2fi and %.2f - %.2fi", realPart, imaginaryPart, realPart, imaginaryPart); } } }