University:
College
Course:
College Computer Science
Academic year:

2023
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77

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3
Author:

20se02ce032

Sahil Vaddoriya20SEO2CE055EXPERIMENT 5Implementation of the given Boolean functions using logic gatesAimTo implement a given Boolean expressions using basic logic gates.Apparatus1. Experimental kit2.Connecting wiresExpressions1) f = A[B+2) f= A +3) f= (B + BC)(B + BC)(B+D)4) AB + ABC +BCACt BC-5) + B + BD + ABD + AC = B+CRealization Diagrams(1) A[B + C(AB+AE)Boolean equation:-= A[B+C(AB.AC)]Y=AB=A[B+C(A+5).Ac]= A[B + CCA(A+B)]AY= A[B + o]B= ABSESH2211: Basics of Electrical & Electronics15 Sahil Vaddoriya20SEO2CE055(2) A+ B[AC + (B+C)D]Boolean equation:=A + B[AC + BD + CD]Y= A + BD= A + BAC + BBD + BCDA= A + ABC + BD + BEDY= A 1 1 + BC) + BD(1+C)= A (1) + BD(1)= A + BDBD(3) (B + BC)(B+BC)(B+D)Boolean equation:-= B(1+c)(B+C)(B+D)Y= B= B(1)(B+C)(B+D)= BB + BC (B+D)By=B(1+C)(B+D)= B(1)(B+D)= BB + BD= B(1+ D)= B16SESH2211: Basics of Electrical & Electronics Sahil Vaddoriya20SEO2CE055(4) AB + ABC + BC = AC + BCBoolean equation:-LHS = A(B+ BC) + BCy = AC + BC= A(B++ c) + BCA= AB + AC+ BC= AB (c + c) + AC+ BCy= ABC + AC + ABC + BC=AC(1+B) + BC(1 +A)B=AC (1) + BC(1)= AC + BCCO= RHS(5) ABC + B + BD + ABD + AC= B+CLHS = C(AB + A) + B + BD(1+ A)-=C(A+)(B+)+1 B + BD= CA + CB + B(1 DCA + CB + BBoolean equation:= CA + (B+B)(B+c)Y= B + C= CA + B+ C= (A+1)C + BBYC= 3+ C= RHSResult: The implementation of Boolen functions by usinglogic gates involve in connecting one logic gates outputto another's input using AND, OR, NAND and NOR gates.Teacher's SignatureTeacher's NoteMarksSESH2211: Basics of Electrical & Electronics17