University:
Duke University
Course:
PHYSICS 133 | The Physics of Sports
Academic year:

2023
Views:

71

Pages:

2
Author:

Pemuda H

Takeoff thrust is inversely proportional to velocity of air coming out of the engine. Aircraft Range (6.3.6) T=D = L () = L/D mgu Overall efficiency no= C/D me LHV →mf= mgu LID 20 LHV mf dm --u ds dm de Set them equal and = dm -u ds mgu LID LHV s = In (m2).. 2o LHV M2 m-initial mass ma-final mass If we aren't dealing with rocket engines, Ae (Pe-Pa) is insignificant (melle-mau) u (ue-u) u Yo - mf LHV FLHV These have been true for a turbojet. For a turbofan.... ue= Жан (1+1) Иен + жас иес тан (1+f) + тас → weighted average of uen and lec should sum up to 1 if ueн лес 1 mf f = man mac (e-u)u No = (1+ man) FLHV → Nomax for ue 2 u= Now range is LHV. Tu s=in()HV u=const. s = me T In Thrust Specific Fuel Consumption (TSFC) (6.3.7) TSFC wf T Turbofan has the best TSFC Brake Specific Fuel Consumption (BSFC) (6.3.8) BSFC = Ps shaft power Equivalent Brake Specific Fuel Consumption (6.3.9) mf mf EBSFC = Pes = Ps+ Teu Brayton Cycle (6.4) Carnot cycle is the most important, but piston engines are heavy Assumptions (1) Working fluid is air (2) mass flow through the engine is constant (3) Heat addition and heat rejection are isobaric processes. (4) Compression and expansion processes are isentropic Turbine 12 Compression 23 Combustion Turbine-inlet temperature, T3 72 = 1- T Carnot Cycle: Power goes from Turbine to Compressor. Want Wout > wc HEATER Wout Cooling comes from the atmosphere 1st Law: 91-2-W1-2 hz +2 - +3= Chit hao ho -W1-2=h20-hi -W3-4-240-hso Wturbh3ohto 92-3 h30-h20 = 9in Wheth3o-hs-(h2o-h1o) →Why hs? Say that kinetic energy = 0 exit of nozzle What gin = Thermal efficiency hso=hs+270 V

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