University:
Duke University
Course:
PHYSICS 137S | Energy in the 21st Century and Beyond
Academic year:

2023
Views:

175

Pages:

2
Author:

Pemuda H

Problem #5 (pg.57) m=29 1000°C m=103 20°C 3 5.4 MPa 20MPa 0.101MPa Is this possible? Find Pmax at 3 Mass- = 22 looking at a at Energy -- Speap (n+2+ge) in do =Pis+ -m, h, m₂h₂ + mg h₃ = 0 =>m, Ti-m₂ T₂ + m3 13-0 T3= m, T,+ m² 12 2nd Law- Sps (in) do 20 -m,5,-m₂S₂ + m3 53 20 Extreme value is when = 0 →52-5,=Cpin()-Rin() →53-5,=CpIn()-Rin() T -ms-mz (s,+Cpin-Rin11) +ms (S,+Cpn-Rin) = 1+2 -Xin [()]+(1+2)[]20 In Two Options: Find P3 or plug in the Inventor's PO to check Inventor is wrong CH.3: Compressible Flows and Shock Waves in Steady Flows Mass Conservation (3.1.1) ne p+df v+dv 0+do →x p+dp T+ dT PV,O,P2 V202 Kdy (2) pvo = const How to Solve a Problem d(pro)=0 pvdo +ρσαν + νσαρ = 0 do+ dv+ σ = 0 George Polya Other Way -pvo + (p+dp) (v+dv)(o+do) = 0 -ρνο + (pv+pdv +vdp) (o+do) = 0 { Ignoring higher order terms -pyo+pro+pvασ + ρσαν + νσαρ=0 do+ y + f = 0 P=0 REVIEW SESSION no cheat sheet • no engines • momentum forces (pressure, viscous, gravitational) Find force on the nozzle ""= - ((A-pande+(P2-Pa)ñ+ SA(p-pa) do Onozzle Spando-o Spido = Frozzle Pa+AP F = Sopñdo •Know laws, corollaries, perpetual motion • Ideal gas is generally a reasonable assumption for this class

Problem #5 Mass Energy

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