University:
Duke University
Course:
PHYSICS 151L | Introductory Mechanics
Academic year:

2023
Views:

416

Pages:

2
Author:

Pemuda H

Fo=-Sprido σ = ροΐας - ερξατ - ορατ = = Dt →since the volume of the differential element is arbitrary to get this, the inside must be zero for any o 0 = 20[ds + Momentum Conservation. d Prove: pxa = Sp → DX Using Reynold's T.T. a(px) 0=20 + 2 = RHS [+ (px)] α φ = RHS d 2(px) + x(pv)+pvvx] d = RHS de + X +0 7X]d 6 = RHS x(+pv))=0 = DX 70 م Dt Now I can say that at = 2 δρότατα do Using Reynold's T.T. on defovde = F + Fs St de + Spy PV (Vn) do = F + Fs 0=20 And for a C.V.. dt Substituting 2(pv) + ατ*=* = Steady, =0, and neglect Fisc *2 pådo dp*=* Mass conservation is always used Steady, p=const FIND D includes some viscosity effects 2 Mass: Steady Assume-0 Momentum Spin) do = +Sendo = - +2t pvde Neglecting F, and viscous forces compared to pressure forces b/2 JU(2)1.dy 6/2 + Vel (1)dx + 6/2 - U+ Sve(x)dx + Sob1210 uly)dy=0 Know ve (x) now 374 14 surface normal are orthogonal b/2 Spui (ut. (-x)) 2.dy + 5^ [ui+ve (x)]] (ui+ve (x)j). (2).dx 0 -612 + puly) (uly)î•î) 1.dy = Fp -pu²½i+fp(ui+ve (x)) Ve (x)dx + pity) i dy = Fo Fp=-pido P = ・ST・(-1) 1.dy-ff-Poj) j (2) dx - - √(-PoT). ↑ (1)dy - - SCP+0P)j-jdx = 0 P and SPod=0 -[Pondo + Sopή] 014 =>-pu²½î+ps" (ui+ve (x)î) ve (x)dx + pou² (y)îdy = - (2↑+Fyj) = b

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