Energy Equation Aerothermodynamics | Duke University

University:
Duke University
Course:
PHYSICS 363 | Thermal Physics
Academic year:

2023
Views:

397

Pages:

2
Author:

Pemuda H

E-Pillielin+Pauze Uzn = 0 Pilin (uit+2)=0 => Uit = Uzt Energy: Pelion) do = - Pás p(h+)(n) do=0 ४ => 2 RT + RT₂ + in += RT- 2 = 2 2 2 10 To 20 P +=+2n→ can solve for the win and urn P in Pi 2 Min M, sino Man = Masin (σ-8) Just substitute this into normal shock eqs. 28 8-1 M 2 2 Uit Meyer: uz acr니다 Prandtl: U, Uznačr tans = (M-1)-1) tano = 2 M₂= f(M, S) = f(M,, 5) P20/P1o (M,, δ) to find o, you use the →o found for air as a starting guess for the Newton-Rafsa Method Pa Ve = 2700m/s Pa = 0.101 MPa Ve Ae= 0.2 m² Pe = 0. 16 MPa Pe me= 60 kg/s A Ae FIND: Thrust fpv (n) do = F+Fs = -Spido pve Aeî = - Spido T= S(Pe-Pa)ñdo Ai = - [pido + pôdo] = A + Ae Ai = - [Pe-Pat Pando + Pendo] Pando + Spendo A = -7 Ae A Ae