Lab 9: Gene Mapping, Crossing Over, Centromere Mapping (Sordaria fimicola)
Homework assignment
1.
a. 2
b. B and C
c. (100 + 100 + 90 + 90)/(1680) x 100% = 22.6 map units
2.
Although Sordaria are usually haploid, at a certain stage they sexually reproduce by fusing two haploid
spores to form a diploid cell. This cell immediately undergoes Meiosis I, Meiosis II, and one round of
Mitosis, two form an eight-cell haploid array. In haploid cells, the genotype always reflects the phenotype,
and so easily visualized alleles (like spore color) can be determined. These two features allow us to study
crossing over during ascus formation.
3.
The first, second, fourth, and fifth asci are the result of second division segregants (i.e. where crossing
over has occurred):
[(30 + 74 + 65 + 43) / (780 x 2)] x 100% = 13.6 map units
4. The first, second, third, and fourth asci are the result of second division segregants (i.e. where
crossing over has occurred):
[(52 + 65 + 120 + 130) / (777 x 2)] x 100% = 23.6 map units
5.
Homologous recombination occurs when, during the chiasma formation where two double-stranded
chromosomes pair closely together, the double-stranded DNA of one chromosome is swapped with
the double-stranded DNA of the other chromosome. This produces the typical second division
segregant patterns in Sordaria. During chiasma formation, it can sometimes happen that a piece of
single-stranded DNA can bind to a single-stranded DNA from a different chromosome. The cell tries
to repair this by converting one strand into the sequence of the other. The upshot is that sister
chromatids are no longer identical, which results in unusual patterns (you could think of it as third
division segregants).
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