Homework #2 Hourly Capacity

S7.14 S7.14 Klassen Toy Company, Inc., assembles two parts (parts 1 and 2): Part 1 is first processed at workstation A for 15 minutes per unit and then processed at workstation B for 10 minutes per unit. Part 2 is simultaneously processed at workstation C for 20 minutes per unit. Workstations B and C feed the parts to an assembler at workstation D, where the two parts are assembled. The time at workstation D is 15 minutes. What is the bottleneck of this process? A: 60 ÷ 15 = 4 units/hour B: 60 ÷ 10 = 6 units/hour C: 60 ÷ 20 = 3 units/hour D: 60 ÷ 15 = 4 units/hour The slowest station is C (3 units/hr), so C is the bottleneck. What is the hourly capacity of the process? Looking at C as the limited feeder of 3 hours which is determined from 60/20. S.7.15 • • S7.15 A production process at Kenneth Day Manufacturing is shown in Figure S7.9. The drilling operation occurs separately from, and simultaneously with, sawing and sanding, which are independent and sequential operations. A product needs to go through only one of the three assembly operations (the operations are in parallel). Which operation is the bottleneck? Drlling: 60/2.4 units=25 min Saw+Sand= 6+4=10 min 60/10=4 Welding 60/2=30 Assembly= 60/0.7=85.71/3 =28.57 Welding is the slowest What is the bottleneck time? Welding: 60/ 2 = 30 min per unit What is the throughput time of the overall system? Saw/ sand = 20 min Drilling= 25 min Welding: 30 min Assembly: 85.714 min Sum of all = 140.714 min If the firm operates 8 hours per day, 20 days per month, what is the monthly capacity of the manufacturing process? 2 units hr * 8 hr/ day*20 days= 320 units month