Student Exploration: Ray Tracing (Mirrors)

Name: Anh Vy Date: 5/8/23 Student Exploration: Ray Tracing (Mirrors) Directions: Follow the instructions to go through the simulation. Respond to the questions and prompts in the orange boxes. Vocabulary: concave mirror, convex mirror, focal point, magnification, real image, reflect, virtual image Prior Knowledge Questions (Do these BEFORE using the Gizmo.) For these questions, it would be helpful to have a metal spoon on hand. If you don’t have one, try to imagine looking at yourself in a spoon. 1. Look at yourself in the front of the spoon (the side where the food sits). What do you see? If I look at myself in front of the spoon I would see my own reflection that has been inverted The front of a spoon is an example of a concave mirror. 2. What do you see when you look at yourself in the back of a spoon? If I look at myself at the back of a spoon, I would see a reflection of myself The back of a spoon is an example of a convex mirror. Gizmo Warm-up The Ray Tracing (Mirrors) Gizmo shows a side view of a light bulb positioned to the left of a mirror. Light rays passing from the light bulb to the mirror are shown. To begin, select the Concave mirror. Turn on Colorize lines. Under Show lines, turn off the Central line and the Line through focal point so that only the Parallel line is showing. 1. The blue dot in front of the mirror is the focal point of the mirror. Move the light bulb on the left around. What is always true about the ray that is reflected from the parallel ray? When we change the light bulb’s position around, the reflected ray passes through the focal point 2. Turn off the Parallel line and turn on the Line through the focal point. Move the light bulb around. What do you notice about the reflected ray in this situation? Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved In this situation the reflected ray is horizontal and parallel to the axis of the mirror Get the Gizmo ready: Activity A: Real and virtual images ● Check that the Concave mirror is selected. ● Turn on the Parallel line, Central line, and Line through focal point. ● Place the light bulb above -24 on the central axis, with the focal point at -12. Introduction: A concave mirror is also called a “converging mirror” because it reflects light rays into a point. A real image is formed where the reflected light rays converge at a point. Unlike a virtual image that forms behind a mirror, a real image can be projected onto a screen. Question: How do mirrors create real and virtual images? 1. Observe: In its current configuration, the distance from the light bulb to the focal point is slightly more than 12 units. The distance from the focal point to the mirror is exactly 12 units. A. What do you notice about the size of the light bulb’s image? Both the light bulb’s seem to be the same size B. What do you notice about the orientation of the light bulb’s image? The light bulb’s image is upside down 2. Investigate: Complete each action described in the table below, and state how that action affects the image. Action Move the light bulb to the left. Effect on image The bulb moves right and gets smaller Move the light bulb to the right. The bulb moves left and gets bigger Move the focal point to the left. The bulb moves left and gets bigger Move the focal point to the right. The bulb moves right and gets smaller 3. Analyze: Examine the results recorded in your table. A. In general, how do the size and position of the image change when the distance between the light bulb and the focal point increases? The light bulb gets smaller and gets closer to the focal point B. In general, how do the size and position of the image change when the distance between the light bulb and the focal point decreases? The light bulb gets bigger and moves further away from the focal point Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved 4. Explore: Move the light bulb to -10 and the focal point to -20. What do you notice about the image when the light bulb is between the focal point and the mirror? The bulb’s image is more larger and its position is further up than the light bulb itself The image is virtual because no light rays are focused there. This virtual image is what an observer would see looking into the mirror. The dashed lines represent the direction that an observer would perceive the reflected light was traveling from. 5. Investigate: Select a Convex mirror, and turn off the Original light lines and the Apparent light lines. Move the light bulb back and forth (but keep it close to the central axis). A. What do you notice about the three lines reflected from the convex mirror? All three lines are formed from the image of the light bulb B. Is the image of the light bulb a real image or a virtual image? Explain. (Hint: Recall that a real image is formed where actual light rays are reflected.) The image of the bulb is a virtual image because there was no real image formed and the bulb was upright which is caused when the rays are diverged C. Move the light bulb back and forth. No matter where the light bulb is located on the central axis, what is always true about size of the image? The image of the bulb is always smaller than the light bulb itself 6. Apply: Which type of mirror would you use for the following applications, and why? A. Cooking a hot dog: I would use a concave mirror since it would focus on just the hotdog and produces a real image instead of a virtual image B. Surveillance in a convenience store: I would use a convex mirror since it shows a wider view of the store Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved Activity B: Get the Gizmo ready: ● Select the Concave mirror. ● Move the light bulb to -15 and the focal point to -10. ● Turn off all lines, and turn on Show ruler. The mirror equation Question: How is position of the image related to the position of the object and the focal length of the mirror? 1. Measure: In this activity, you will measure the relationships between several values: do: Distance between object and mirror f: Distance between focal point and mirror di: Distance between image and mirror What are the current values of each of these variables? (Note: You can use the ruler to measure do and di.) do = 15 f = 10 di = 30 2. Gather data: Measure di for each of the following values of do and f. For the last two rows of the table, use your own values of do and f. (Note: If the light bulb is to the right of the focal point (do < f), the image is virtual and di is negative.) do f di 15 10 30 1/15≈0.0667 1/30≈0.0333 1/10≈0.1 25 10 17 1/25≈0.04 1/17≈0.0588 1/10≈0.1 20 10 20 1/20≈0.05 1/20≈0.05 1/10≈0.1 30 10 15 1/30≈0.0333 1/15≈0.0666 1/10≈0.1 3. Calculate: Find the reciprocal of each value and fill in the last three columns of the table. 4. Analyze: For each row of the table, find the sum of 0.1 0.0988 What do you notice? and 0.1 . Record these values here: 0.0999 The focal point to mirror approximately has the same measurement Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved 5. Make a rule: Express the relationship between 1/do + 1/di = , , and as an equation. 1/f This equation is called the mirror equation. For the spherical mirror shown in this Gizmo, the equation works well so long as the object is close to the central axis. 6. Practice: You place a light bulb 8 cm in front of a concave mirror. You then move a sheet of paper back and forth in front of the mirror. The image of the light bulb focuses on the paper when the paper is 12 cm in front of the mirror. What is the focal length of the mirror? 4.8 Show your work: 1/12 + ⅛ = 1/f = (8+12)/12*8 = 20/96 = 4.8 cm 7. Practice: A light bulb is placed 20 cm in front of a concave mirror with a focal length of 8 cm. How far from the mirror will the image of the light bulb be focused? 13.3 Show your work: 1/20 + 1di + ⅛ di = 13.33cm 8. On your own: Does the mirror equation work for a convex mirror? Use the Gizmo to find out and describe your findings below. (Hint: In this situation, di and f are negative.) Yes. If I place the light bulb at -20, the focal point will be at 20. do=20 f=20 d=-10 1/20 - 1/20 = -1/20 Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved Get the Gizmo ready: Activity C: ● Check that the Concave mirror is selected. ● Move the light bulb to -15 and the focal point to -10. Magnification Introduction: Mirrors are often used to change the size of an image. The magnification of an image is equal to the ratio of the image height to the object height. Some mirrors, such as the mirrors in reflecting telescopes, produce images that are greatly magnified. Other mirrors, such as the mirrors in side-view mirrors on cars, produce images that are reduced in size. Question: What determines the magnification of an image? 1. Measure: What are the current values of these variables? do = 15 f = 10 di = 30 2. Measure: In addition to the variables you explored in the previous activity, you will investigate several others. Measure each of these variables and list their values below. Pay close attention to the sign conventions as you do this. ho: Object height (always positive) hi: Image height (negative if image is inverted) so: Focal point to object distance: so = f – do si: Focal point to image distance: si = f – di ho = 3 hi = 5 so = 6 si = 20 3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill in the last two rows. do f di ho hi so si 15 10 30 3 6 5 20 2.0 2.0 2.0 2.0 30 15 30 3 3 15 15 1.0 1.0 1.0 1.0 20 10 20 3 3 10 10 1.0 1.0 1.0 1.0 4. Calculate: Calculate the given ratios to fill in the last four columns of the table. (Hint: As long as the image is a real, upside-down image, all four ratios will be negative.) 5. Analyze: What do you notice about the four ratios? They are all the same Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved 6. Make a rule: 1. The magnification of an image is equal to the ratio of the image height to the object height. If the image is inverted, the magnification is negative. Using the ratios from the table on the previous page, write three equations to calculate magnification: di/do 7. Manipulate: If = f/so si/f , what is true about the product of so and si? it is equal to f^2 Use the data you collected on the previous page to confirm that this relationship holds. 8. Practice: A candle is placed 14 cm in front of a concave mirror. The image of the candle is focused on a sheet of paper that is exactly 21 cm in front of the mirror. A. What is the magnification of the image? m=1.5 B. What is the focal length of this mirror? (Hint: Use the mirror equation.) f=8.4cm Show your work: M = v/u = 21/14 = 1.5 1/di + 1/do = 1/f 1/21 + 1/14 = 1/f 2 + 3/42 = 1/f 5/42 = 1/f F = 42/5 F = 8.4 9. Practice: A candle is placed 9 cm in front of a concave mirror with a focal length of 6 cm. A. How far from the mirror will the image be located? v = 18cm B. What is the magnification of this image? m=2 Show your work: M = v/u = 18/9 = 2 V = 1/f = 1/u = 1/v ⅙ = 1/9 + 1/v = ⅙ - 1/9, 1/v = 1/18 V = 18cm Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved 10. Challenge: When an object is between the focal point and a concave mirror an upright virtual image is created behind the mirror. Because the image is upright, the value of hi is positive. In this case, what must be true about the values of di, so, and si? si, do, and hi would be negative Reproduction for educational use only. Public sharing or posting prohibited. © 2020 ExploreLearning™ All rights reserved