University:
Kentucky State University
Course:
PHY 212 | General Physics II
Academic year:

2023
Views:

405

Pages:

8
Author:

Tyshawn Shaffer

**Figure: Q1** [Image of a graph with voltage (V) on the y-axis and time (t) on the x-axis, showing a sinusoidal wave] **Question 1:** In Fig. Q1: a. The minimum power Pmin = b. The average power Pavg = c. The reactive power Q = d. The peak power Pmax = **Figure: Q2** [Image of a square wave graph with voltage (V) on the y-axis and time (t) on the x-axis] **Question 2:** The RMS value of the signal shown in Fig. Q2 is: a. 86.7 V b. 8.166 V c. 8.615 V d. 6.867 V **Figure: Q3** [Image of a graph with two sinusoidal waveforms: v(t) and i(t)] **Question 3:** If the load is composed of two elements in series, then the current i(t) flows to the load is: a. 8 cos(100πt - 60°) b. 15 cos(100πt + 30°) c. 10 cos(100πt - 30°) d. 12 cos(100πt + 60°) **Question 7:** Fig. Q7 shows the instantaneous power p(t), where the voltage is given in the form: v(t) = 100 cos(2πft + θ) V. [Image of a power waveform with time on the x-axis and power (W) on the y-axis] **The frequency of the voltage f is:** a. 10 kHz b. 200 kHz c. 50 kHz d. 100 kHz **One of the numerical expressions of the instantaneous power p(t) is:** a. 400 - 500 cos 143.13° cos 2wt + 500 sin 143.13° sin 2wt b. none of these c. 400 - 500 cos (2wt + 143.13°) d. 400 + 500 cos (2wt - 36.87°) e. 400 + 900 cos(2wt) + 300 sin(2wt) Question 7: Fig. Q7 shows the instantaneous power p(t) absorbed by the load and the voltage v(t) applied to it. The load is composed of 2 elements in series. The current i(t) is: a. 15 cos(100πt + 30°) b. none of these c. 12 cos(100πt + 60°) d. 8 cos(100πt - 60°) e. 10 cos(100πt - 30°) Question 8: A three-phase balanced voltage source feeds the load shown in Fig. Q5. The VAB = 400∠20°. The |ZAB| = |ZBC| = |ZCA| and the three-phase load absorbs 4000 W. threephase circuit with a deltaconnected load The line current IaA is: a. none of these b. 19.32∠-45° A c. 10∠30° A d. 19.32∠45° A e. 10∠-45° A **Q:** A three-phase balanced voltage source feeds the load shown in Fig. Q4. |Z| = 5/30° Ω, VAN = 400∠60° Vrms [Image of a three-phase circuit with a delta-connected load] The VBN = a. 421.43∠-55.3° A b. 267∠-40° A c. 250.32∠-30° A d. 267.5∠-132° A e. 243.73∠-186° A