University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

44

Pages:

2
Author:

Caroline Mcfarland

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 22. Joint FBDs: FJL F 500 lb = KL = 1212 1212 480 Joint L: FJL = FKL = 1262.50 lb FJL = 1263 lb T ! FKL = 1263 lb C ! Comparing joint G to joint L: FGH = 1263 lb T ! FGI = 1263 lb C ! Joint J: ΣFx = 0: 1188 (1262.50 lb ) − FHJ = 0 1212 FHJ = 1237.50 lb, ΣFy = 0: FJK − 240 (1262.50 lb ) − 500 lb = 0 1212 FJK = 750.00 lb, Joint H: ΣFx = 0: FHJ = 1238 lb T ! 1237.50 lb − FJK = 750 lb C ! 1188 4 (1262.50 lb ) + FHK = 0 1212 5 FHK = 0 ! ΣFy = 0: FHI − 240 3 (1262.50 lb) − 500 lb − (0) = 0 1212 5 FHI = 750 lb C ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. COSMOS: Complete Online Solutions Manual Organization System Joint I: ΣFx = 0: 1188 (1262.50 lb ) − FIK = 0 1212 FIK = 1237.50 lb, ΣFy = 0: FIN − 240 (1262.50 lb ) − 750.00 lb = 0 1212 FIN = 1000.00 lb, Joint K: ΣFx = 0: FIK = 1238 lb C ! 1237.50 lb − FIN = 1000 lb C ! 1188 4 (1262.50 lb ) − FKN = 0 1212 5 FKN = 0 ! ΣFy = 0: FKO − 240 (1262.50 lb) − 750.00 lb = 0 1212 FKO = 1000 lb C ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.