COSMOS Chapter 8 Solution 44 | Answer Key - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2019
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 44. FBD rod: 3 in. N B − ( 4.5 in.) cosθ  W = 0 cosθ ΣM A = 0: or N B = (1.5cos 2 θ )W Impending motion: FB = µ s N B = (1.5µ s cos 2 θ )W = ( 0.3cos 2 θ )W ΣFx = 0: N A − N B sin θ + FB cosθ = 0 N A = (1.5cos 2 θ )W ( sin θ − 0.2 cosθ ) or Impending motion: FA = µ s N A = ( 0.3cos 2 θ )W ( sin θ − 0.2 cosθ ) ΣFy = 0: FA + N B cosθ + FB sinθ − W = 0 ( FA = W 1 − 1.5cos3 θ − 0.3cos 2 θ sin θ or ) Equating FA’s 0.3cos 2 θ ( sin θ − 0.2cosθ ) = 1 − 1.5cos3 θ − 0.3cos 2 θ sinθ 0.6cos 2 θ sin θ + 1.44cos3 θ = 1 Solving numerically Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. θ = 35.8° W

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