COSMOS Chapter 9 Solution 22 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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326

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2
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hacedoras1kxy

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 22. Have: A = ( 2a )( 3b ) − 1 ( 2a )( b ) 2 = 5ab Have: JP = Ix + I y Where: I x = ∫ y 2dA a 2b b − x a = 2∫ 0 ∫ = y 2dydx 3 2 a 3  b   − − 2 b x  ∫ ( )  a   dx 3 0     2  x4  = b3  8x + 3  3  4a  = And a 0 11 3 ab 2 I y = ∫ x 2dA a 2b 2 b x dydx − x a = 2∫ 0 ∫  a  b  = 2∫ 0 x 2  2b −  − x   dx  a   a 1 4 2 = 2b  x3 + x  4a  0 3 = 11 3 ab 6 continued COSMOS: Complete Online Solutions Manual Organization System Then: Also: JP = kP = = 11 3 11 3 ab + a b 2 6 JP = 11 ab a 2 + 3b 2 6 kP = 11 a + 3b 2 30 ( ) JP A 11 ab a 2 + 3b 2 6 5ab ( ) )

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