COSMOS Chapter 6 Solution 65 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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324

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1
Author:

Tyshawn Shaffer

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 65. FBD Truss: ΣFx = 0: ΣM F = 0: Ax = 0 ( 2.4 m )(8 kN ) + ( 5.1 m )( 6 kN ) − ( 7.5 m ) Ay =0 A y = 6.64 kN FBD Section ABC: Since only BE can provide the downward force necessary for equilibrium, it must be in tension, so FCD = 0 ΣFy = 0: 6.64 kN − 6 kN − FBE = 1.21143 kN, ΣM = 0: FBE = 1.211 kN T ! (1.68 m ) FCE − ( 2.4 m )( 6.64 kN ) = 0 FCE = 9.4857 kN, ΣFx = 0: 1.68 FBE = 0 3.18 9.4857 kN + FCE = 9.49 kN T ! 2.7 (1.21143 kN ) − FBD = 0 3.18 FBD = 10.51 kN C ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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