University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

396

Pages:

1
Author:

salcignofi9

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 50. FBD Truss: Distance between loads = 1.5 m ΣFx = 0: By symmetry, Ax = 0 A y = K y = 18 kN FBD Section ABC: FBD Section ABC: ΣM D = 0: (1.5 m ) FCE + (1.5 m )( 6 kN ) − ( 3 m )(18 kN − 3 kN ) = 0 FCE = 22.5 kN T ! ΣM A = 0: (1.8 m ) 4 FCD − (1.5 m )( 6 kN ) = 0 5 FCD = 6.25 kN T ! ΣFy = 0: 18 kN − 3 kN − 6 kN − 8 4 FBD + ( 6.25 kN ) = 0 17 5 FBD = 29.8 kN C ! Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.