COSMOS: Complete Online Solutions Manual Organization System
Chapter 9, Solution 3.
At x = 0:
First note:
At x = a :
a = k ( 2b − b )
k =
∴ x=
Have
2
c = −b
or
or
0 = k (b + c)
2
a
b2
a
2
y − b)
2(
b
I y = ∫ x 2dA
=∫
a
2
y − b)
2b b 2 (
0
0
∫
x 2dxdy
3
1 2b a
2
= ∫ 0 2 ( y − b ) dy
3
b
2b
1 a3 1
7
=
× ( y − b)
6
3b
7
b
=
1 3
ab
21
Iy =
1 3
a b
21