COSMOS Chapter 8 Solution 47 | Michigan State University - Edubirdie

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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2019
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 47. φ s = tan −1 µ s = tan −1 ( 0.40 ) = 21.801°, and slip impends at wedge/lower block, wedge/wedge, and upper block/incline interfaces. FBD Upper block and wedge: R2 530 lb = sin 41.801° sin 38.398° R2 = 568.76 lb FBD Lower wedge: P 568.76 lb = sin 51.602° sin 68.199° P = 480 lb Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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