COSMOS Chapter 4 Solution 32 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

376

Pages:

1
Author:

Dixie Summers

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 32. Free-Body Diagram: Geometry: Distance AD = (0.9)2 + (0.375)2 = 0.975 m Distance BD = (0.5)2 + (0.375)2 = 0.625 m Equilibrium for beam: (a) ΣM C = 0: 0.375   0.375  T  ( 0.9 m ) −  T  ( 0.5 m ) = 0  0.975   0.625  (135 N )( 0.7 m ) −  T = 146.250 N (b) ΣFx = 0: or T = 146.3 N  0.9   0.5  Cx +  T  (146.250 N ) +  T  (146.250 N ) = 0 0.975    0.625  C x = − 252.00 N ΣFy = 0:  0.375   0.375  Cy +  T  (146.250 N ) +  T  (146.250 N ) − 135 N = 0  0.975   0.625  C y = − 9.0000 N Thus: C = C x2 + C y2 = and θ = tan −1 Cy Cx ( − 252 )2 + ( − 9 )2 = tan −1 = 252.16 N 9 = 2.0454° 252 C = 252 N 2.05°

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