COSMOS Chapter 4 Solution 80 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

473

Pages:

1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 80. Free-Body Diagram: Note that the member is a three-force body. In the free-body diagram, E is the intersection between the lines of action of the three forces. From the free-body diagram:  15  α = tan −1   = 61.928°  8  8 β = tan −1   = 33.690°  12  From the force triangle: α − β = 61.928° − 33.690° = 28.238° 180° − α = 180° − 61.928° = 118.072° Using the law of sines: T − 18 lb T C = = sin(α − β ) sin β sin(180° − α ) T − 18 lb T C = = sin ( 22.238° ) sin ( 33.690° ) sin(118.072°) Then: (T − 18 lb ) sin ( 33.690° ) = T sin ( 28.238° ) T = 122.414 lb and or T = 122.4 lb (122.414 lb ) sin (118.072°) = C sin ( 33.690° ) C = 194.723 lb or C = 194.7 lb 33.7°

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