COSMOS Chapter 6 Solution 88 | Michigan State University - Edubirdie

University:
Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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1
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behend6abs

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 88. FBD Frame: Note: In analysis of entire frame, location of M is immaterial. Note also that AB, BC, and FG are two force members. ΣM H = 0: ( 6 ft ) I y − 180 lb ⋅ ft = 0, ΣFy = 0: 30 lb − 5 FAB = 0, 13 ΣM C = 0: ( 2.5 ft )  I y = 30.0 lb ! (a) FBD AI: 12  78 lb − FFG  = 0,  13  ΣFx = 0: FBC − 12 78 lb − 72 lb = 0, 13 FAB = 78.0 lb 22.6° ! FGH = 72.0 lb ! FBC = 144.0 lb ! (b) FBD AI: FAB = 78.0 lb As above, ΣFy = 0 yields Then:  12  ΣM C = 0: ( 2.5 ft )  78.0 lb − FFG  − 180 lb ⋅ ft = 0  13  22.6° ! FFG = 0 ! ΣFx = 0: FBC − 12 ( 78.0 lb ) = 0, 13 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. FBC = 72.0 lb !

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