COSMOS Chapter 8 Solution 9 | Answer Key - Edubirdie

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2019
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 9. FBD Block: For impending motion. φ s = tan −1 µ s = tan −1 ( 0.40 ) φ s = 21.801° Note β1,2 = θ1,2 − φ s 10 lb 15 lb = sinφs sinβ1,2 From force triangle:  15 lb  33.854° sin ( 21.801° )  =  10 lb  146.146° β1,2 = sin −1  55.655° So θ1,2 = β1,2 + φ s =  167.947° So (a) equilibrium for 0 ≤ θ ≤ 55.7° (b) equilibrium for 167.9° ≤ θ ≤ 180° Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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