COSMOS Chapter 9 Solution 113 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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1
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Hundebuchesn

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 113. Mass = m = ρ tA I mass = ρ tI area = Area = A = m I area A 1 2 πa 2 I AA′, area = I DD′, area = I AA′, mass = I DD′, mass = (a) 2 I BB′ = I DD′ − m ( AC ) = 1π 4 1 4  a  = πa 2 4  8 m m 1 4 1 2 I AA′, area = π a  = ma 1 2  8 A  4 πa 2 1 2  4a  ma − m   4  3π  = ( 0.25 − 0.1801) ma 2 2 I BB′ = 0.0699 ma 2 (b) Eq. ( 9.38 ) : I CC ′ = I AA′ + I BB′ = 1 2 ma + 0.0699ma 2 4 I CC ′ = 0.320 ma 2

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