COSMOS Chapter 3 Solution 121 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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322

Pages:

1
Author:

Interpoluium

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 121. ΣF : R = R A = Rλ λ BC Have λ BC = where ( 42 in.) i − ( 96 in.) j − (16 in.) k ∴ RA = 106 in. 21.2 lb ( 42i − 96j − 16k ) 106 or R A = ( 8.40 lb ) i − (19.20 lb ) j − ( 3.20 lb ) k ΣM A : rC/ A × R + M = M A Have where rC/ A = ( 42 in.) i + ( 48 in.) k = 1 ( 42i + 48k ) ft 12 = ( 3.5 ft ) i + ( 4.0 ft ) k R = ( 8.40 lb ) i − (19.20 lb ) j − ( 3.20 lb ) k M = −λ BC M = −42i + 96 j + 16k (13.25 lb ⋅ ft ) 106 = − ( 5.25 lb ⋅ ft ) i + (12 lb ⋅ ft ) j + ( 2 lb ⋅ ft ) k Then i j k 3.5 0 4.0 lb ⋅ ft + ( −5.25i + 12 j + 2k ) lb ⋅ ft = M A 8.40 −19.20 −3.20 ∴ M A = ( 71.55 lb ⋅ ft ) i + ( 56.80 lb ⋅ ft ) j − ( 65.20 lb ⋅ ft ) k or M A = ( 71.6 lb ⋅ ft ) i + ( 56.8 lb ⋅ ft ) j − ( 65.2 lb ⋅ ft ) k .

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