COSMOS Chapter 3 Solution 76 | Michigan State University - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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2
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salcignofi17

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 76. Have M = M1 + M 2 + M P From Problem 3.73 solution: M1 = ( 400 lb ⋅ in.) i + ( 960 lb ⋅ in.) j M 2 = ( 220 lb ⋅ in.) i + ( 528 lb ⋅ in.) j + (192 lb ⋅ in.) k Now M P = rE/ A × PE rE/ A = (19.2 in.) i + ( 8 in.) j − ( 44 in.) k PE = ( 52.5 lb ) j Therefore i j k M P = 19.2 8 − 44 0 52.5 0 = ( 2310 lb. in.) i + (1008 lb. in.) k and M = M1 + M 2 + M P = [(400 + 220 + 2310)i + (960 + 528)j + (192 + 1008)k ] lb ⋅ in. = ( 2930 lb ⋅ in.) i + (1488 lb ⋅ in.) j + (1200 lb ⋅ in.) k M = ( 2930 )2 + (1488)2 + (1200 )2 = 3498.4 lb ⋅ in. or M = 3.50 kip ⋅ in. continued . COSMOS: Complete Online Solutions Manual Organization System λ = M 2930i + 1488j + 1200k = M 3498.4 = 0.83753i + 0.42534 j + 0.34301k cosθ x = 0.83753 or cosθ y = 0.42534 or θ y = 64.8° cosθ z = 0.34301 or θ z = 69.9° . θ x = 33.1°

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