University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

471

Pages:

2
Author:

Arielle Armstrong

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 123. Free-Body Diagram: ( (a) ) W = mg = (15 kg ) 9.81 m/s 2 = 147.15 N First note TEH = λ EH TEH   − ( 0.3 m ) i + ( 0.12 m ) j − ( 0.2 m ) k  T  = T = EH − ( 0.3) i + ( 0.12 ) j − ( 0.2 ) k    EH 2 2 2 0.38 ( 0.3) + ( 0.12 ) + ( 0.2 ) m   From free-body diagram of rectangular plate ΣM x = 0: (147.15 N )( 0.1 m ) − (TEH ) y ( 0.2 m ) = 0  0.12    TEH  ( 0.2 m ) = 0  0.38   or (147.15 N )( 0.1 m ) −  or TEH = 232.99 N or TEH = 233 N (b) ΣFx = 0: Ax + (TEH ) x = 0  0.3  Ax −   ( 232.99 N ) = 0  0.38  ∴ Ax = 183.938 N continued COSMOS: Complete Online Solutions Manual Organization System ΣM B( z -axis ) = 0: − Ay ( 0.3 m ) − (TEH ) y ( 0.04 m ) + W ( 0.15 m ) = 0  0.12 − Ay ( 0.3 m ) −  ( 232.99 N ) ( 0.04 m ) + (147.15 N )( 0.15 m ) = 0  0.38  or ∴ Ay = 63.765 N ΣM B( y -axis ) = 0: Az ( 0.3 m ) + (TEH ) x ( 0.2 m ) + (TEH ) z ( 0.04 m ) = 0  0.3   Az ( 0.3 m ) −   ( 232.99 N )  ( 0.2 m ) −  0.38   or  0.2    ( 232.99 )  ( 0.04 m ) = 0   0.38   ∴ Az = 138.976 N and A = (183.9 N ) i + ( 63.8 N ) j + (139.0 N ) k ΣFy = 0: Ay + By − W + (TEH ) y = 0  0.12  63.765 N + By − 147.15 N +   ( 232.99 N ) = 0  0.38  ∴ By = 9.8092 N ΣFz = 0: Az + Bz − (TEH ) z = 0  0.2  138.976 N + Bz −   ( 232.99 N ) = 0  0.38  ∴ Bz = −16.3497 N and B = ( 9.81 N ) j − (16.35 N ) k