COSMOS Chapter 9 Solution 151 - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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167

Pages:

1
Author:

Nossardisd7p

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 151. From the solution to Problem 9.147 m1 = 105.676 × 10−3 lb ⋅ s 2 /ft m3 = 5.1874 × 10−3 lb ⋅ s 2 /ft m2 = 26.419 × 10−3 lb ⋅ s 2/ft m4 = 10.8451 × 10−3 lb ⋅ s 2/ft First note that symmetry implies I x′y′ = I y′z ′ = I z ′x′ = 0 for each component 0 I uv = I u′v′ + mu v = mu v Now ( Iuv )body so that Then = Σmu v  1.5  0.5   0.75  0.5  I xy = Σmx y = 105.676 × 10−3 lb ⋅ s 2 /ft  ft  ft  + 26.419 × 10−3 lb ⋅ s 2 /ft  ft  ft   12  12   12  12  ( ) ( ( ) )  0.75  0.5  + 5.1874 × 10 −3 lb ⋅ s 2 /ft  ft  ft   12  12   4 × 1.4 in.   1 ft    0.8  − 10.8451 × 10−3 lb ⋅ s 2 /ft  3 in. − ft     π   12 in.      ( ) = ( 550.40 + 68.799 + 13.5089 − 144.952 ) × 10−6 lb ⋅ ft ⋅ s 2 = 487.76 × 10−6 lb ⋅ ft ⋅ s 2 or I xy = 0.488 × 10−3 lb ⋅ ft ⋅ s2 continued

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