COSMOS Chapter 8 Solution 103 | Michigan State University - Edubirdie

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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2019
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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 103. FBD A: ΣFx = 0: TA − WA sin 30° = 0, TA = WA 2 FBD B: ΣFx′ = 0: WB sin 30° − TB = 0, TB = WB 2 For mB min , motion of B impends up incline π And But 0.50 TA = e 3 = 1.68809 TB m A WA T = = A = 1.68809 mB WB TB so mB min = 5.9238 kg From hint, β is not dependent on shape of C For mB max , motion of B impends down incline π so 0.50 mB W T µ = B = B = e s β = e 3 = 1.68809 mA WA TA so mB max = 16.881 kg For equilibrium Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. 5.92 kg ≤ mB ≤ 16.88 kg

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