COSMOS Chapter 8 Solution 134 | Michigan State University - Edubirdie

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COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 134. FBDs Top block: (a) Note: With the cable, motion must impend at both contact surfaces. ΣFy = 0: N1 − 40 lb = 0 F1 = µ s N1 = 0.4 ( 40 lb ) = 16 lb Impending slip: ΣFx = 0: Bottom block: ΣFy = 0: T − F1 = 0 T − 16 lb = 0 N 2 − 40 lb − 60 lb = 0 Impending slip: T = 16 lb N 2 = 100 lb F2 = µ s N 2 = 0.4 (100 lb ) = 40 lb ΣFx = 0: FBD blocks: N1 = 40 lb − P + 16 lb + 16 lb + 40 lb = 0 P = 72.0 lb (b) Without the cable, both blocks will stay together and motion will impend only at the floor. ΣFy = 0: Impending slip: ΣFx = 0: N − 40 lb − 60 lb = 0 N = 100 lb F = µ s N = 0.4 (100 lb ) = 40 lb 40 lb − P = 0 P = 40.0 lb Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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