COSMOS Chapter 6 Solution 79 - Edubirdie

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Michigan State University
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ERG 160 | Success in Science, Technology, Engineering, and Mathematics
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2019
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COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 79. FBD Frame: ΣM A = 0: ( 0.25 m ) Dx − 400 N ⋅ m = 0 D x = 1600 N E x = 1600 N ∴ E y = 1600 N FBD member DF: Note BE is a two-force member, so Ex = Ey ΣFx = 0: 1600 N − E x = 0, ΣM D = 0: − ( 0.50 m )(1600 N ) + ( 0.75 m ) C − 400 N ⋅ m = 0 C = 1600 N ΣFy = 0: Dy − 1600 N + 1600 N = 0 Dy = 0 Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

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