COSMOS Chapter 8 Solution 28 | Answer Key - Edubirdie

University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
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478

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1
Author:

Arielle Armstrong

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 28. From FBD Whole, and neglecting weight of clamp compared to 550 lb plate, P = − W Since AB is a two-force member, B is vertical and B = W . FBD BCD: ΣM C = 0: (1.85 in.)W − ( 2.3 in.) D cos 40° − ( 0.3 in.) D sin 40° = 0, D = 0.94642W FBD EG: ( 0.9 in.) NG − (1.3 in.) FG − (1.3 in.) N D cos 40° = 0 ΣM E = 0: Impending slip: FG = µ s NG Solving: ( 0.9 − 1.3µ s ) NG = 0.94250W (1) FBD Plate: By symmetry NG = NG′ , ΣFy = 0: FG = FG′ = µ s NG 2 FG − W = 0, Substitute in (1): ( 0.9 − 1.3µ s ) FG = W , 2 NG = W 2µ s W = 0.94250W 2µ s Solving, µ s = 0.283, Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. µsm = 0.283

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