COSMOS: Complete Online Solutions Manual Organization System
Chapter 3, Solution 45.
Have
rC = ( 2.25 m ) k
JJJG
CE
TCE = TCE
CE
( 0.90 m ) i + (1.50 m ) j − ( 2.25 m ) k
TCE = (1349 N )
( 0.90 )2 + (1.50 )2 + ( −2.25 )2 m
= ( 426 N ) i + ( 710 N ) j − (1065 N ) k
Now
M O = rC × TCE
i
j
k
= 0
0
2.25 N ⋅ m
426 710 −1065
= − (1597.5 N ⋅ m ) i + ( 958.5 N ⋅ m ) j
∴ M x = −1598 N ⋅ m, M y = 959 N ⋅ m, M z = 0 W
.
COSMOS Chapter 3 Solution 45
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