University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

162

Pages:

1
Author:

plenceplubparun2

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 152. For equivalence Σ F: FA + FB + FC + FD = R C R C = − ( 5 lb ) j − ( 3 lb ) j − ( 4 lb ) k − ( 7 lb ) i ∴ R C = ( −7 lb ) i − ( 8 lb ) j − ( 4 lb ) k Also for equivalence ΣM C : rA′/C × FA + rB′/C × FB + rD′/C × FD = M C or MC i j k i j k i j k = 0 0 −1.5 in. + 1 in. 0 −1.5 in. + 0 1.5 in. 1.5 in. 0 5 lb 0 0 −3 lb 0 −7 lb 0 0 = ( −7.50 lb ⋅ in. − 0 ) i  + ( 0 − 4.50 lb ⋅ in.) i + ( −3.0 lb ⋅ in. − 0 ) k  + (10.5 lb ⋅ in. − 0 ) j + ( 0 + 10.5 lb ⋅ in.) k  or M C = − (12.0 lb ⋅ in.) i + (10.5 lb ⋅ in.) j + ( 7.5 lb ⋅ in.) k .

COSMOS Chapter 3 Solution 152

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