University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

296

Pages:

1
Author:

hacedoras1kxy

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 57. ( M OA = λ OA ⋅ rC/O × P Have ) where From triangle OBC Since or a 2 ( OA) x = ( OA) z = ( OA ) x tan 30° = ( OA)2 = ( OA ) x + ( OA ) y + ( OAz ) 2 a 1  a =   2 3  2 3 2 2  a  2 a a =   + ( OA) y +   2 2 3 2 ∴ Then rA/O = and λ OA = ( OA) y = 2 2 a2 − a2 a2 2 − =a 4 12 3 a 2 a i +a j+ k 2 3 2 3 2 i+ 2 j+ k 3 2 3 P = λ BC P = = ( a sin 30°) i − ( a cos30°) k a P i − 3k 2 ( ) rC/O = ai ∴ M OA 1 2 = 1 1 = = . 2 1 3 2 3 P ( a )   0 0 2 0 − 3 aP  2  −  (1) − 3 2  3  aP aP M OA = 2 2 ( ) ( P)

COSMOS Chapter 3 Solution 57

of 1

Description

Free up your schedule!

Take 5 seconds to unlock