University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2024
Views:

222

Pages:

1
Author:

marthamanayay9qr8

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 52. Free-Body Diagram: Geometry: Distance BD = (1.8)2 + (4)2 = 4.3863 m Note also that: W = mg = (160 kg)(9.81 m/s2) = 1569.60 N With MA = 360 N ⋅ m clockwise: (i.e. corresponding to Tmax ) ΣM A = 0:  1.8   − 360 N ⋅ m – [(540 N) cos 15o](5.6 m) +   Tmax  (4 m) = 0  4.3863   Tmax = 1998.79 N or Tmax = 1.999 kN With MA = 360 N ⋅ m counter-clockwise: (i.e. corresponding to Tmin ) ΣM A = 0:  1.8   360 N ⋅ m – [(540 N) cos 15o](5.6 m) +   Tmin  (4 m) = 0  4.3863   Tmin = 1560.16 N or Tmin = 1.560 kN

COSMOS Chapter 4 Solution 52

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