University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

393

Pages:

2
Author:

FrextWhestembki

COSMOS: Complete Online Solutions Manual Organization System Chapter 9, Solution 98. From the solution to Problem 9.72: I xy = 501.1875 in 4 From the solution to Problem 9.80: I x = 865.6875 in 4 I y = 4758.75 in 4 1 I x + I y = 2812.21875 in 4 2 ( ) 1 I x − I y = −1946.53125 in 4 2 ( ) I ave = Now and R  Ix − I y     2  ( I x , I xy ) , X: The Mohr’s circle is defined by the point 2 I xy2 Y: ( I y, − I xy ) 1 I x + I y = 2812.2 in 4 2 ( ) 2 1946.53125 ) + 501.18752 2010.0 in 4 continued COSMOS: Complete Online Solutions Manual Organization System tan 2θ m = − I xy  Ix − I y     2  =− 501.1875 = 0.2575, −1946.53125 2θ m = 14.4387° or θ m = 7.22° counterclockwise Then I max, min = I ave ± R = ( 2812.2 ± 2010.0 ) in 4 or I max = 4.82 × 103 in 4 and I min = 802 in 4 Note: From the Mohr’s circle it is seen that the a axis corresponds to I min and the b axis corresponds to I max .

COSMOS Chapter 9 Solution 98

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