University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

457

Pages:

2
Author:

Nossardisd7p

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 149. Free-Body Diagram: Express forces in terms of their rectangular components: ( ) ( ) ( ) WAB = − (1.25 kg/m ) 9.81 m/s 2 ( 0.9 m ) j = − (11.0363 Ν ) j WBC = − (1.25 kg/m ) 9.81 m/s 2 ( 0.3 m ) j = − ( 3.6788 Ν ) j WCD = − (1.25 kg/m ) 9.81 m/s 2 (1.35 m ) j = − (16.5544 Ν ) j uuur CE =T T=T CE −0.9 i + 1.2 j − 1.35 k ( − 0.9 ) 2 2 + (1.2 ) + ( −1.35 ) 2 = T ( −3 i + 4 j − 4.5 k ) 45.25 continued COSMOS: Complete Online Solutions Manual Organization System λ AD uuur AD = = AD 0.9 i − 0.3 j − 1.35 k ( 0.9 ) 2 2 + ( − 0.3) + ( −1.35 ) 2 = 6 2 9 i− j− k 11 11 11 rG/ A = ( 0.45 m ) i rC/ A = ( 0.9 m ) i − ( 0.3 m ) j rB/ A = ( 0.9 m ) i rH/A = ( 0.9 m ) i − ( 0.3 m ) j − ( 0.675 m ) k Now, ΣM AD = 0: ( ) ( ) ( ) ( ) λ AD ⋅ rG/ A × WAB + λ AD ⋅ rC/ A × T + λ AD ⋅ rB/ A × WBC + λ AD ⋅ rH / A × WCD = 0 −2 −9 −2 −9 6 6 − 2 −9 6 T 1 1 + 0.9 0.45 0 0   + 0.9 − 0.3 0 0 0   11 11 45.25    11  − 3 4 − 4.5 0 −11.0363 0 0 − 3.6788 0 6 −2 −9 1 + 0.9 − 0.3 − 0.675   = 0  11  0 −16.5544 0 4.0634 − 0.32840T + 2.7089 + 6.0950 = 0 Solving for T: T = 39.182 N or T = 39.2 N

COSMOS Chapter 4 Solution 149

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