University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

136

Pages:

1
Author:

Mireya Blevins

COSMOS: Complete Online Solutions Manual Organization System Chapter 3, Solution 107. (a) Have ΣM D : 0 = M − ( 0.8 in.)( 40 lb ) − ( 2.9 in.)( 20 lb ) cos 30° − ( 3.3 in.)( 20 lb ) sin 30° or M = 115.229 lb ⋅ in. or M = 115.2 lb ⋅ in. Now, R is oriented at 45° as shown (since its line of action passes through B and D). 0 = ( 40 lb ) cos 45° − ( 20 lb ) cos15° Have ΣFx′ : − ( 90 lb ) cos (α + 45° ) or α = 39.283° or (b) ΣFx : α = 39.3° Rx = 40 − 20sin 30° − 90cos 39.283° = − 39.663 lb Now . R= 2 Rx or R = 56.1 lb 45.0°

COSMOS Chapter 3 Solution 107

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