University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

281

Pages:

1
Author:

hekeldigzjbz

COSMOS: Complete Online Solutions Manual Organization System Chapter 8, Solution 6. FBD Block: ( ) W = ( 20 kg ) 9.81 m/s 2 = 196.2 N For θ min motion will impend up the incline, so F is downward and F = µs N ΣFy = 0: ΣFx = 0: (1) + ( 2 ): N − ( 220 N ) sin θ − (196.2 N ) cos 35° = 0 F = µ s N = 0.3 ( 220 sin θ + 196.2 cos 35° ) N (1) ( 220 N ) cosθ (2) − F − (196.2 N ) sin 35° = 0 0.3 ( 220 sin θ + 196.2cosθ ) N = ( 220 cosθ ) N − (196.2sin 35° ) N or 220cosθ − 66sin θ = 160.751 Solving numerically: Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies. θ = 28.9°

COSMOS Chapter 8 Solution 6

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