University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

393

Pages:

1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 6, Solution 110. Member FBDs: 4 FDG = 0 5 ΣM A = 0: ( 0.3 m ) FBF − ( 0.9 m ) ΣM E = 0: 4 − ( 0.3 m ) FBF + ( 0.6 m ) FDG − ( 0.9 m )( 0.8 kN ) = 0 5 Solving: FBE = − 3 kN, FBF = − 7.2 kN so FBF = 7.20 kN T FDG = 3.00 kN C Vector Mechanics for Engineers: Statics and Dynamics, 8/e, Ferdinand P. Beer, E. Russell Johnston, Jr., Elliot R. Eisenberg, William E. Clausen, David Mazurek, Phillip J. Cornwell © 2007 The McGraw-Hill Companies.

COSMOS Chapter 6 Solution 110

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