University:
Michigan State University
Course:
ERG 160 | Success in Science, Technology, Engineering, and Mathematics
Academic year:

2019
Views:

41

Pages:

1
Author:

Quintin Ware

COSMOS: Complete Online Solutions Manual Organization System Chapter 4, Solution 28. Free-Body Diagram: Geometry: ( 2.52 )2 + ( 0.462 )2 Distance BC = = 2.562 m Equilibrium for mast: (a)  2.52    TBC  ( 0.75 m ) − ( 90 N )( 2.16 m ) − (135 N )( 0.66 m ) = 0   2.562   ΣΜ A = 0: TBC = 384.30 N (b) or TBC = 384 N  2.52  Ax −   ( 384.30 N ) = 0  2.562  ΣFx = 0: Ax = 378.00 N ΣFy = 0:  0.462  Ay +   ( 384.30 N ) − 135 N − 90 Ν = 0  2.562  Ay = 155.700 N Ax2 + Ay2 = ( 378.00 )2 + (155.700 )2 Ay 155.700 = 22.387° 378.00 Thus: A= and θ = tan −1 Ax = tan −1 = 408.81 N ∴ A = 409 N 22.4°

COSMOS Chapter 4 Solution 28

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