COSMOS: Complete Online Solutions Manual Organization System
Chapter 4, Solution 54.
Free-Body Diagram:
For both parts (a) and (b)
(
)
l cos (θ + 30° ) cos 30° W − l cos θ + 30o T
ΣM D = 0:
(
)
(
)
+ l sin θ + 30o cos 60o W + l sin θ + 30o T = 0
or W cos(θ + 60°) + T sin (θ + 30° ) − cos (θ + 30° ) = 0
(a)
For T = 0, (1) gives
cos (θ + 60° ) = 0
(b)
(1)
or θ = 30.0°
For T = W , (1) gives:
cosθ cos 60° − sin θ sin 60° + sin θ cos 30° + cosθ sin 30°
− cosθ cos 30° + sin θ sin 30° = 0
or tan θ sin 30° + ( cos 60° + sin 30° − cos 30° ) = 0
Solving for θ :
tan θ = 2 ( cos 30° − 1)
or θ = −150000°
or θ = −15.00°
COSMOS Chapter 4 Solution 54
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