Magnetic Field on the Axis of a Circular Coil | Santa Fe College - Edubirdie

University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

477

Pages:

5
Author:

Jabin F.

Title: Magnetic field on the axis of a circular coil Labels: Outer part (R) θ d dB dBz Z I Equations: dℓ = R dθ dB = μ₀I dℓ / (4πr²) dBz = dB cos θ r² = R² + d² dBz = μ₀I dℓ R / (4π(R² + d²)^(3/2)) ∫ dBz = μ₀I R² / (2(R² + d²)^(3/2)) Bnet Binner I a θ 1 2 3 B1 B2 B3 Equations: B = μ₀I / (2a) * (θ / (2π)) Bnet = (μ₀I / (2a)) * (1/4) Bnet = (μ₀I / (2a)) * (1 - 2/π) Bnet = μ₀I / (6a) B1 = -μ₀I / (4πa) * 0 B2 = μ₀I / (4a) * 0 B3 = μ₀I / (4πa) * θ Bnet = (μ₀I / (4πa)) * (1 + π + 1) Equations: Numerous equations are presented, including: Bnet = (μ₀I / (4πa)) * (1 + π) μ₀ / (4π) = 10⁻⁷ q = 10⁻² m I = 1A Bnet = (10⁻⁷ * 1) / (10⁻²) * (1 + 3.14) Bnet = 5.14 * 10⁻⁵ Tesla 1T = 10⁴G 1G = 10⁻⁴T Bnet = 0.514 gauss Bnet = (3/2) * (μ₀I / (2R)) + (μ₀I / (4πR)) * (π/2) Labels: Bnet μ₀ a I q Tesla G Ans. (Option-D) duej.31 P*y-43 5 R I Here contribution is circle (1 + 2) Circle

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