Name: EM Wave Propagation Through Isotropic, Linear and Dielectric
Brand: EduBirdie
Rating: 5.0 (23 reviews)

University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

475

Pages:

5
Author:

Jabin F.

# EM wave propagation through isotropic linear dielectric - free current Dielectric (insulator) → electrical free charge = 0, Jf = 0, Sf = 0,#Lossless eq.n → max.n → #linear B = μH, E = εE #isotropic → scalar scalar ∇.D = ρf → ∇.(εE) = 0 → ε∇.E = 0 → ∇.E = 0∇.B = 0∇xE = -∂B/∂t∇xB = μ∂E/∂t (eqn (i), (ii), and (iii) is same as vacuum case)but in eqn (iv) → μ₀ → με₀ → ε → Speed of wave (v) = 1/√(με) = 1/(√(μ₀μ)√(ε₀ε))v = c/√(μrεr) μr > 1, εr > 1 → v < c Relative permeability or dielectric constant If Refractive index of the medium is n →thenv = c/n Compare above eqn.Refractive Index → n = √(μrεr)of the medium. → If Relative permeability (μr) not givenwe takeμr = 1(non-magnetic medium) All the parameters of Dielectric medium would be# same that of free space with following changes. Free Space Isotropic Linear Dielectricμ₀ → με₀ → εc → v Ques-70page-74 non-magnetic medium → μr = 1εr = 4 (given) ω = 10^8E = (-i + j√3) exp[j(ωt - kz)] refractive index (n) = √(μrεr)v = c/n = c/√2 v = c / √(μrεr) = c / 2 → |R| = λ / 4 = c / (4ω) |R| = (2 * 10^8) / (3 * 10^8) = 2/3 In option (a) and option (d), |R| = 2/3. We satisfy ∇.E = 0 → |R| = 2/3. Option (a): In dielectric medium, RE = 0. Option (d): RE ≠ 0. → Option (a) is correct. Ques-65 page-77 E = i * sin(kz - ωt) ↑ = ~~= (1/2) * ε * c * E^2 / Z = (1/8) * 3 * 10^8 * 8.85 * 10^-12 * (5)^2 = 26.55 * 10^-4 W/m^2~~

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