University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

380

Pages:

6
Author:

Jabin F.

Induced current in the loop: (I = \frac{\mathcal{E}}{R_{L}} = \frac{VBd}{R_{L}}) Ques.5: (x < 0, B = 0) (x > 0, B = B_{2}) Clockwise Thumb If angle between B and area vector is not changing then: (\mathcal{E} = \oint (\vec{v} \times \vec{B}) \cdot d\vec{l}) (\mathcal{E} = \oint (v_{x}\hat{i} \times B_{2}\hat{k}) \cdot d\vec{l}) (\mathcal{E} = -vB_{2}h) If resistance of loop given RL: (I = \frac{VBh}{R_{L}}) So option (b) is right If loop completely enters into magnetic field then: (\mathcal{E} = 0) Two rails of a railroad track are insulated from each other and from the ground and are connected by a millivoltmeter. What is the reading of the millivoltmeter when a train travels at the speed 90 km/hr down the track? Assume that the vertical component of the Earth's magnetic field is 0.2 gauss and that the tracks are separated by 1 meter. Use 1 gauss = 10^-4 Tesla = 10^-4 V.sec/m^2 (a) 10 (b) 1 (c) 0.2 (d) 180 Soln: MV (millivoltmeter) R (resistance) 0.2G (magnetic field) 1 meter (distance between tracks) ↑ (upward direction) -ve (negative) → (rightward direction) v = 90 km/hr tve (positive) Thumb ε = ∫(v × B) · dl ε = VBd