University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

213

Pages:

5
Author:

Jabin F.

Section 1 Equation: ∇⋅E = 4πρ Derivation: ε0 * ∇⋅E = ρ ∇⋅E = 4πρ / ε0 ∇⋅E = 4πρ Equation: μ0 * ε0 = 1/c^2 Derivation: μ0 = 1 / (ε0 * c^2) = 4π / c^2 Equation: ∇ x E = -(1/c) * ∂B/∂t Section 2 Equation:

= (I0^2 * a^4 * ω^4 * π(4π)) / (12c^5) Reference: Question 61, Page-91 Distortionless condition: R/G = L/C Reference: Question 58, Page-33 Capacitor types: Parallel plate capacitor Spherical plate capacitor Cylindrical capacitor Transmission line: Coaxial cable Default: Assume free space Dimensions: a = 1mm, b = 3mm Section 1 Reference: Question 30, Page-97 Diagram: A circle with radius R, centered at the origin. Points A, B, and C are marked on the circle. Angles θ and φ are labeled. Conditions: R >> a, angle between R and a is 90 degrees, 0 ≤ θ ≤ 360 degrees, θ1 = 90 degrees. Equation: I ∝ sin^2(θ) Section 2 Equation: Ia = ( / ) * (r1^2 / R^2) Calculation: Ia = (1/2) * (1/4) = 1/8 Conclusion: For this case, I(R, 0, 0) = 4 and I(0, 2R, 0) = 1/8 Detailed Description The image appears to be a handwritten note or diagram related to a physics problem, likely involving a circular configuration or wave propagation. It consists of two sections: Section 1 Introduces a circle with labeled points and angles. States conditions and a proportionality relationship between I and sin^2(θ). Section 2 Presents an equation for Ia, which seems to be related to intensity or amplitude. Calculates Ia for two specific cases. Section 1 Equation: Ia = ( / ) * (r1^2 / R^2) Calculation: Ia = (1/2) * (1/4) = 1/8 Conclusion: For this case, I(R, 0, 0) = 4 and I(0, 2R, 0) = 1/8 Section 2 Reference: Question 20, Page-96 Equation: ⃗A = (1/2) * ⃗B x ⃗r Conclusion: ⃗A = 0 (Coulomb gauge) Conditions: ∇⋅⃗A = 0 (Coulomb gauge), ∇⋅⃗A + (1/c) * ∂Φ/∂t = 0 (Lorentz gauge)