University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

190

Pages:

6
Author:

Jabin F.

Section 1 Equations: Ue = (1/2) * ε0 * E^2 Um = (1/2) * (1/μ) * B^2 Uem = (1/2) * (ε0 * E^2 + (1/μ) * B^2) Ue / Um = (ε0 / μ) * (E / B)^2 = (1 + εr) Ue = με * (E / B)^2 Ue / Um = 1 for free space and dielectric E / B = c Section 2 Equation: E^2 / B^2 = (ω / k)^2 = (1 + εr) Conclusion: For a good conductor, εr >> 1, Ue << Um Section 1 Reference: Question 32433, Page-73 Equation: ⃗E = (1/2) * E0 * exp[i(⃗R⋅⃗k - ωt)] Equation: ⃗R = (z/2) * (k cosφ + ik sinφ) Variables: α = k cosφ, β = k sinφ Equation: ⃗R = (z/2) * (α + iβ) Section 2 Equation: ⃗R × ⃗E = (z/2) * (α + iβ) × ŷ = +ŷ Equation: E0 * ⃗E = E0 * ŷ Equation: ⃗E = -2k * sinφ * ŷ Section 1 Reference: Question 5, Page-69 Given: εr = 12 Equations: Jc = (1/2) * σw Jq = ε0 * (∂E/∂t) σ'' = (ε0 * εr * 2πf) / (2s) σ'' = (4π * ε0 * εr * f) / (-2x^2 * s) σ'' = (12 * 100 * 10^6) / (9 * 10^9 * 50) = 2.61 * 10^-3 S/m Section 2 Reference: Question 7, Page-69 Equations: Jq = ε0 * (∂E/∂t) = ε0 * (∂V/∂x) V = V0 * cos(ωt) Jq = -V0 * ε0 * ω * sin(ωt) / d Section 3 Reference: Question 55, Page-76 Conditions: ω ↑, n ↑ (normal dispersion) ω ↑, n ↓ (anomalous dispersion) ω ↑, n = const. (non-dispersive medium)