University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

74

Pages:

5
Author:

Jabin F.

# Energy stored in an inductor: Um = 1/2 * L * T^2 Um = 1/2 * (B * H) dz for free space: H = B / μ₀ Ques. 35 Page-64 B = Nμ₀I / 2πR (mag field of toroid) flux through single turn: ϕ_single = Nμ₀IA / 2πR Total flux ϕ_total = N^2μ₀IA / 2πR Self Inductance L = ϕ / I = μ₀N^2A / 2πR (a) A=small Ques.20 Page-61 ∮ E dl = -∫ (∂B'/∂t) ds Bin = μ₀nI z I(t) #Inside (ra) ∫ E dl = -∫ μ₀n (∂I/∂t) ds E_in = -μ₀nπr^2 / 2πr * (∂I/∂t) => E_in = -μ₀nπr^2 / 2 * (∂I/∂t) * Direction of induced electric field is same as direction of induced current. How can define din of induced Ɛ? (or - Ɛ) => If t↑, I↑, ∂I/∂t = +ve => Ɛ∝(-ɸ) => If t↑, I↓, ∂I/∂t = -ve => Ɛ∝(ɸ) # *outside (r>R) ∮ E dl = -μ₀n (∂I/∂t) πr^2 E_out = -μ₀nπr^2 / 2πr * (∂I/∂t) E_out = μ₀nπr^2 / 2πr * (∂I/∂t) (option-c) # :: in magnetostatics A_out = μ₀nπr^2 / 2πr * I ɸ A_in = μ₀nπr^2 / 2πr * I ɸ => Ɛ = -∂A/∂t in electrodynamics L ↔ M (mass) I ↔ v (velocity) q ↔ x (position) 1/C ↔ K (force constant) Conclusion ⇒ Changing in v is difficult if m is large. ⇒ Changing in I is difficult if L is large. Ques-37 Page-64 # let current is I (Total Turns 8) Bin = μ₀nI ϕ = (μ₀nτ)(\pi R^{2})(n~l) Total Turns. ϕ = LI Self Inductance per unit length L/u = μ₀n^2πR^2 (option-9)