Condition Interference Maxima and Condition Diffraction Minima - Edubirdie

University:
Santa Fe College
Course:
ETS 2527C | Electromechanical Components and Mechanisms
Academic year:

2024
Views:

154

Pages:

5
Author:

Jabin F.

Condition for interference maxima: dsinθ = mλ ⇒ Interference maxima (a+b)sinθ = mλ - (i) (a+b) = d m = 0, 1, 2, 3... Condition for diffraction minima: asinθ = nλ - (ii) m = 1, 2, 3... absent spectra (7th order) due to interference minima from diffraction (a+b)sinθ = mλ asinθ = nλ ⇒ (a+b)/a = m/n = 7 Ques. 56 Page: 90 λ = 1.2 μm D = 1.8 m tanθ ≈ sinθ = x / D ⇒ sinθ = 0.3 * 10⁻² / 1.8 = 1/6 * 10⁻² Diffraction minima: asinθ = mλ a = (mλ) / (sinθ) = (1 * 1.2 * 10⁻⁶) / (1/6 * 10⁻²) a = 0.72 mm (slit's width) Interference maxima: (a+b)sinθ = mλ (a+b)/a = 7 (a+b) = 7 * 0.72 d = 5.04 mm (option-a) Ques. 45 Page-87 a = w (a+b) = αw Here Interference + diffraction Interference maxima: (a+b)sinθ = mλ ⇒ αw sinθ = mλ Diffraction minima: asinθ = mλ ⇒ wsinθ = mλ Distant Screen θ → 0 (small) (a) zero intensity for m = 1, 2, 3... ⇒ missing minima (diffraction) ⇒ asinθ = mλ ⇒ wsinθ = mλ zero for m = 0 (d) m = 0 ⇒ m = 2n if n = 0 ⇒ m = 0 this is in interference maxima (option wrong) So for m = 0, intensity maxima.

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