University:
University of Colorado Boulder
Course:
PHYS 1110 | General Physics 1
Academic year:

2021
Views:

180

Pages:

4
Author:

Lia Sullivan

Forces Virtual Lab: m11:111 H sliii811 mm ' * Go to r . . - ; ••• If P.af ip: Foi 111 ?• .. 53 ? CDIS 3 " 10:59 AM , You will be starting with a crate that has a mass of 100 kg and a coefficient of sliding friction of 0.3 and a coefficient of static friction of 0.5 1. Draw the Free Body Diagram (a picture showing the forces on the crate) before you apply any force. f., 5 button and record what happens. 2. Add 10 N of applied force, and push the Include a free body diagram showing all the forces. £ fafp button. What changed? 3. Add 100 N of applied force and push the ‘ShU 6U.ctv - QXVOOS 4. Use the friction equation to calculate how much force would be required to get it Try it out. What happened? How did you fix the moving. Show your work here problem to get it moving? ) m e W o t cticUti ^l bub if UOOL * ^ oN bo ) lb itctozA nuy^c , 5. What happened as the crate moved up the ramp? Show the free body diagram while the crate is on the ramp. What force is working against your applied force? 6. Reset all. Predict what you think would happen if you increased the angle. What actually happened? Explain why you saw what you saw. 7. Reset all. Predict what you think would happen if you decreased the angle. Try it out. Why? Cx&AXjLd ijrvfv UC&JJ. j5° / (j e^ ^ 8. Place the crate on the ramp with the angle at 20°. What is true about the parallel force and the friction force if the crate does not go down the ramp? Slowly increase the angle until the block JUST starts to move. Use the angle to calculate ps and compare to the given vaiue for |_is for the crate. - Fp if no cLppli -ed U lb fKcJves QJ- ^ £7°! "3 UA - * *5 JS9. Calculate how much force you would have to apply to the crate to get it to go at constant speed up the 30° ramp. Show your work below and record your answer to the tenth of a Newton (Hint: Remember it's moving now, so which |x do you need to use?) CJUX CX^rC- pjcUx u~ Fgw + ' si ' # ^ ^ ~ + 3L 6 %o - 75*/. / A/ - Fapp doS 30 = 10. Go to the "Forces Graph" tab. Reset all. Input your applied force and push play. Stop the crate before it crashes into the wall. Is your net force = 0 (Fsum 11)? What does that tell you about the motion of the crate? tp, FSM.II ~ o' FruJ- Jl rwcic^ 1/ » 11. Place the block at the top of the 30° ramp (Position = 8.9 m). What is the net force on the block down the ramp? (Show your calculation below). What is the acceleration of the block down the ramp? (Include in your calculation). What would be the final velocity of the block at the bottom of the ramp? 6 W Frn-f " Fjii ^ rvup * 3^ ~ (\ o .& Y& ^ “ " ( iPoX ^3 ^' V doSOO t2TWhat7orce is acting on the crate once it hits the flat part at the bottom of the iv ramp? What is the magnitude and direction of that force? Fp c -^ V A/ ^ \rc ^ 13. What will be the acceleration of the crate on the flat part at the bottom of the ramp? p= ryy^ - - ^ OL 14. Calculate how far the crate should slide at the bottom. Try it out. How did your calculation compare to the applet result? _ "2 V f - Vi x =- g. i ^ SLi- O

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