University:
Viterbo University
Course:
PHYS 260 | University Physics I
Academic year:

2023
Views:

25

Pages:

6
Author:

TomAnd45

Sheet A=5 m², L=0.5cm AT=30°c glass ? By using combicdivity Heat Transport Equation KAAT L =08x5 30 05462 =24 KW 2A-23 L=5cm AT=25°C -25.3W AT L KL = 25.3 x 5162 2.3+25 K = 0.022 W BL-Sma glass L 8 ATA k(Tz-T) L -0.8 29+30 54163 20.8 59 A1-A =9440 W/m2 b) Storm is parallel teges with air gap of 6 cm ATA? storm- Lal kar-0.025 w/c AT () AT ΔΤΑ ++ (29+30) 08 2015 108 24.45 W/m2 5 at 14) T Tislac ceft A Steady state Khu 818 w/mic ag =? ATA /19 (KA 100-T KA T2:120c on Right t-min,Q:20 J Steady state from Right taleft At? for 9=205 at (6) AT from (a) = A 24 K 20 (12-10) 2460 2 24 RA:330 At 20=2KA (12-10) Ku (100-T) = Kg (T-20) 318 419 [100-1] = [1-20] 741-0747=T-20 74.1+20=1-74T 94.1-1.747 T=54°c At L 20 = 11042 KA 308 Rockration 5W ATR Az 0.6mm2 T Bottenan laut- ST 5- T: 3574.7 K 7=5cm, his 15 cm Cylinder 8:0.8, 1:50, T90°C له P 9 =501273 323 k A(T) 2 0856706 (763)-(313)] 8 A = 18.45 W A PAE (TET) 295.8 -2.95W P295 A 18.45 P016 P Extra problems 25 K109K4 K3:0.8K1 Te:-15 C Thermd stredy stats QATI AKATI AKTA L 4 AT 4507 L 0.9k 0.9 ATE 15-8°C 1035